-16t^2+1,600=0

Solution for -16t^2+1,600=0 equation:

-16t^2+1.600=0

We add all the numbers together, and all the variables

-16t^2+1.6=0

a = -16; b = 0; c = +1.6;
Δ = b2-4ac
Δ = 02-4·(-16)·1.6
Δ = 102.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{102.4}}{2*-16}=\frac{0-\sqrt{102.4}}{-32}
=-\frac{\sqrt{}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{102.4}}{2*-16}=\frac{0+\sqrt{102.4}}{-32}
=\frac{\sqrt{}}{-32}
$